Решите систему неравенств: 3x^2-10x-8>0; x<=5.

\[\left\{ \begin{matrix} 3x² - 10x - 8 > 0\ \ (1) \\ x \leq 5\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\ \end{matrix} \right.\ \]

\[(1)D = 100 + 96 = 196\]

\[x_{1} = \frac{10 + 14}{6} = 4\]

\[x_{2} = \frac{10 - 14}{6} = \frac{2}{3}\]

\[Ответ:\left( - \infty;\ - \frac{2}{3} \right)(4;5\rbrack.\]