Решите систему уравнений: 2x-3y=-12; x+2y=1.

\[\left\{ \begin{matrix} 2x - 3y = - 12\ \ \\ x + 2y = 1\ \ \ | \cdot 2 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} 2x - 3y = - 12 \\ 2x + 4y = 2\ \ \ \ \ \ \\ \end{matrix} \right.\ \text{\ \ }( - )\]

\[- 7y = - 14\]

\[y = 2.\]

\[\left\{ \begin{matrix} x = 1 - 2y \\ y = 2\ \ \ \ \ \ \ \ \ \ \ \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ }\left\{ \begin{matrix} x = 1 - 4 \\ y = 2\ \ \ \ \ \ \ \ \\ \end{matrix} \right.\ \text{\ \ \ \ }\left\{ \begin{matrix} x = - 3 \\ y = 2\ \ \ \\ \end{matrix} \right.\ \ \]

\[Ответ:( - 3;2).\]