Решите систему уравнений: y-x=2l y^2+4x=13.

\[\left\{ \begin{matrix} y - x = 2\ \ \ \ \ \ \ \\ y^{2} + 4x = 13 \\ \end{matrix} \right.\ \]

\[\left\{ \begin{matrix} y = x + 2\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\ (x + 2)^{2} - 4x = 13 \\ \end{matrix} \right.\ \]

\[x^{2} + 4x + 4 - 4x - 13 = 0\]

\[x^{2} = 9\]

\[x_{1} = 3;\ \ x_{2} = - 3;\]

\[y_{1} = 3 + 2 = 5;\]

\[y_{2} = - 3 + 2 = - 1.\]

\[Ответ:(3;5);( - 3; - 1).\]