Решите уравнение: ((2^x )^2·2^7)/2^5 =16².

\[\frac{\left( 2^{x} \right)^{2} \cdot 2^{7}}{2^{5}} = 16^{2}\]

\[2^{2x} \cdot 2^{2} = 2^{8}\]

\[2^{2x} = 2^{6}\]

\[2x = 6\]

\[x = 3.\]