Решите уравнение: 2x^4+6x^3-8x^2-24x=0.

\[2x^{4} + 6x^{3} - 8x^{2} - 24x = 0\]

\[2x^{3} \cdot (x + 3) - 8x \cdot (x + 3) = 0\]

\[2x(x + 3)(x - 2)(x + 2) = 0\]

\[x = 0;\ \ \ x = - 3;\ \ \ x = 2;\ \ \ \ \]

\[x = - 2\]

\[Ответ:x = 0;\ x = - 3;\ x = \pm 2.\]