Решите уравнение: 4x^2+20x+25=0;

\[\ 4x² + 20x + 25 = 0\]

\[D = b^{2} - 4ac = 400 - 4 \cdot 4 \cdot 25 =\]

\[= 400 - 400 = 0\]

\[x = \frac{- 20}{8} = - \frac{10}{4} = - \frac{5}{2} = - 2,5\]

\[Ответ:x = - 2,5.\]