Решите уравнение: 4x^2-7x-2=0;

\[\ 4x² - 7x - 2 = 0\]

\[D = b^{2} - 4ac = 49 - 4 \cdot 4 \cdot ( - 2) =\]

\[= 49 + 32 = 81\]

\[x_{1} = \frac{7 - 9}{8} = - \frac{2}{8} = - \frac{1}{4}\]

\[x_{2} = \frac{7 + 9}{8} = \frac{16}{8} = 2\]

\[Ответ:x = - \frac{1}{4}\ \ \ и\ \ \ x = 2.\]