\[(x + y)^{2} + (x - 1)^{2} = 0\]
\[\left\{ \begin{matrix} x + y = 0 \\ x - 1 = 0 \\ \end{matrix} - \right.\ \text{\ \ \ \ \ \ }\]
\[\left\{ \begin{matrix} y + 1 = 0 \\ x = 1\ \ \ \ \ \ \ \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ }\]
\[\left\{ \begin{matrix} y = - 1 \\ x = 1\ \ \ \ \\ \end{matrix} \right.\ \]
\[Ответ:(1;\ - 1).\]