Решите уравнение: x^2-6x-27=0.

\[x² - 6x - 27 = 0\]

\[D = ( - 6)^{2} - 4 \cdot 1 \cdot ( - 27) =\]

\[= 36 + 108 = 144\]

\[x_{1} = \frac{6 + \sqrt{144}}{2 \cdot 1} = \frac{6 + 12}{2} =\]

\[= \frac{18}{2} = 9;\]

\[x_{2} = \frac{6 - \sqrt{144}}{2 \cdot 1} = \frac{6 - 12}{2} =\]

\[= - \frac{6}{2} = - 3.\]

\[Ответ:x = 9;\ x = - 3.\]