\[\frac{x(2 - x)}{2} + \frac{x(3 + 2x)}{4} = 1\ \ \ \ \ \ | \cdot 4\]
\[2x(2 - x) + x(3 + 2x) = 4\]
\[4x - 2x^{2} + 3x + 2x^{2} = 4\]
\[7x = 4\]
\[x = \frac{4}{7}.\]