Решите уравнение: (x-7)(x+7)-11x-30=(x+5)^2+(x-2)^2.

\[(x - 7)(x + 7) - 11x - 30 =\]

\[= (x + 5)^{2} + (x - 2)^{2}\]

\[x^{2} - 49 - 11x - 30 =\]

\[= x^{2} + 10x + 25 + x^{2} - 4x + 4\]

\[x^{2} - 2x^{2} - 11x - 6x - 79 - 29 = 0\]

\[- x^{2} - 17x - 108 = 0\ \ \ \ \ \ \ \ \ | \cdot ( - 1)\]

\[x^{2} + 17x + 108 = 0\]

\[D = 289 - 432 < 0 -\]

\[нет\ корней.\]

\[Ответ:нет\ корней.\]