Упростите выражение 4x^2/(2x-3)+9/(3-2x)-2x-8.

\[\frac{4x^{2}}{2x - 3} + \frac{9}{3 - 2x} - 2x - 8 =\]

\[= \frac{4x^{2}}{2x - 3} - \frac{9}{2x - 3} - (2x + 8)^{\backslash 2x - 3} =\]

\[= \frac{4x^{2} - 9 - 4x^{2} - 16x + 6x + 24}{2x - 3} =\]

\[= \frac{- 10x + 15}{2x - 3} = \frac{- 5 \cdot (2x - 3)}{2x - 3} = - 5.\]

\[Ответ:\ - 5.\]