Вычислите: 5^-2; (-3)^-3; (1/12)^-1; (2,83)^0.

Ответ:

\[5^{- 2} = \frac{1}{5^{2}} = \frac{1}{25};\text{\ \ \ \ }\]

\[( - 3)^{- 3} = \frac{1}{( - 3)^{3}} = \frac{1}{- 27};\]

\[\left( \frac{1}{12} \right)^{- 1} = 12;\text{\ \ \ \ }\]

\[(2,83)^{0} = 1.\]