Задание 3: Решить неравенства \(7a + 6 \leq 12a\) и \(86 - 14 \geq 4b\).

\(7a + 6 \leq 12a\)\(6 \leq 5a\)\(a \geq \frac{6}{5}\). \(86 - 14 \geq 4b\)\(72 \geq 4b\)\(b \leq 18\). Ответы: \(a \geq \frac{6}{5}\), \(b \leq 18\).