\[x^{2} + 6x - 13 = 0\]
\[x_{1} + x_{2} = - 6;\ \ x_{1} \cdot x_{2} = - 13\]
\[2x_{1}x_{2} + 3x_{1} + 3x_{2} =\]
\[= 2x_{1}x_{2} + 3\left( x_{1} + x_{2} \right) =\]
\[= 2 \cdot ( - 13) + 3 \cdot ( - 6) =\]
\[= - 26 - 18 = - 44.\]
\[Ответ:\ - 44.\]