\[b_{4} = 18;\ \ q = \sqrt{3}:\]
\[b_{4} = b_{1} \cdot q^{3}\]
\[b_{1} = \frac{b_{4}}{q^{3}}\]
\[b_{1} = \frac{18}{\left( \sqrt{3} \right)^{3}} = \frac{18}{3\sqrt{3}} = \frac{6}{\sqrt{3}} = \frac{6\sqrt{3}}{3} = 2\sqrt{3}.\]
\[Ответ:2\sqrt{3}.\]