Решите уравнение: ((3^x )^3·3^5)/3²=27².

\[\frac{\left( 3^{x} \right)^{3} \cdot 3^{5}}{3^{2}} = 27²\]

\[\frac{3^{3x} \cdot 3^{5}}{3^{2}} = \left( 3^{3} \right)^{2}\]

\[3^{3x} \cdot 3^{3} = 3^{6}\]

\[3^{3x} = 3^{3}\]

\[3x = 3\]

\[x = 1.\ \]