Решите уравнение: x^2/16-x^(\2)/8=(x+1)/3.

\[\frac{x^{2}}{16} - \frac{x^{\backslash 2}}{8} = \frac{x + 1}{3}\text{\ \ \ \ \ \ }\]

\[\frac{x^{2} - 2x^{\backslash 3}}{16} = \frac{x + 1^{\backslash 16}}{3}\ \]

\[3\left( x^{2} - 2x \right) = 16(x + 1)\]

\[3x^{2} - 6x - 16x - 16 = 0\]

\[3x^{2} - 22x - 16 = 0\]

\[D = 121 + 48 = 169\]

\[x_{1} = \frac{11 + 13}{3} = \frac{24}{3} = 8;\ \ \ \ \]

\[x_{2} = \frac{11 - 13}{3} = - \frac{2}{3}\]

\[Ответ:\ - \frac{2}{3};\ \ 8.\]