\[\frac{3 - \sqrt{3}}{\sqrt{6} - \sqrt{2}} = \frac{\sqrt{3}\left( \sqrt{3} - 1 \right)}{\sqrt{2}\left( \sqrt{3} - 1 \right)} = \frac{\sqrt{3}}{\sqrt{2}} =\]
\[= \sqrt{\frac{3}{2}} = \sqrt{1,5}.\]